2(t-2)+8t=5(2t+3)-13

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Solution for 2(t-2)+8t=5(2t+3)-13 equation: 



2(t-2)+8t=5(2t+3)-13

We move all terms to the left:

2(t-2)+8t-(5(2t+3)-13)=0

We add all the numbers together, and all the variables

8t+2(t-2)-(5(2t+3)-13)=0

We multiply parentheses

8t+2t-(5(2t+3)-13)-4=0



We calculate terms in parentheses: -(5(2t+3)-13), so:

5(2t+3)-13

We multiply parentheses

10t+15-13

We add all the numbers together, and all the variables

10t+2

Back to the equation:

-(10t+2)



We add all the numbers together, and all the variables

10t-(10t+2)-4=0

We get rid of parentheses

10t-10t-2-4=0

We add all the numbers together, and all the variables

-6!=0

There is no solution for this equation

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