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6(x+1)=3-2(6x/4)
We move all terms to the left:
6(x+1)-(3-2(6x/4))=0
We add all the numbers together, and all the variables
6(x+1)-(3-2(+6x/4))=0
We multiply parentheses
6x-(3-2(+6x/4))+6=0
We multiply all the terms by the denominator
6x*4))-(3-2(+6x+6*4))=0
We add all the numbers together, and all the variables
6x*4))-(3-2(6x+24))=0
We add all the numbers together, and all the variables
6x*4))-(3-2(6x=0
Wy multiply elements
24x^2=0
a = 24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·24·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{48}=0$
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