-5(7-8x)-(1-x)=4(x-5)

Solution for -5(7-8x)-(1-x)=4(x-5) equation:

-5(7-8x)-(1-x)=4(x-5)

We move all terms to the left:

-5(7-8x)-(1-x)-(4(x-5))=0

We add all the numbers together, and all the variables

-5(-8x+7)-(-1x+1)-(4(x-5))=0

We multiply parentheses

40x-(-1x+1)-(4(x-5))-35=0

We get rid of parentheses

40x+1x-(4(x-5))-1-35=0


We calculate terms in parentheses: -(4(x-5)), so:

4(x-5)

We multiply parentheses

4x-20

Back to the equation:

-(4x-20)


We add all the numbers together, and all the variables

41x-(4x-20)-36=0

We get rid of parentheses

41x-4x+20-36=0

We add all the numbers together, and all the variables

37x-16=0

We move all terms containing x to the left, all other terms to the right

37x=16

x=16/37

x=16/37