6(x+1)-8=2x+4(-1+x)

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Solution for 6(x+1)-8=2x+4(-1+x) equation: 



6(x+1)-8=2x+4(-1+x)

We move all terms to the left:

6(x+1)-8-(2x+4(-1+x))=0

We add all the numbers together, and all the variables

6(x+1)-(2x+4(x-1))-8=0

We multiply parentheses

6x-(2x+4(x-1))+6-8=0



We calculate terms in parentheses: -(2x+4(x-1)), so:

2x+4(x-1)

We multiply parentheses

2x+4x-4

We add all the numbers together, and all the variables

6x-4

Back to the equation:

-(6x-4)



We add all the numbers together, and all the variables

6x-(6x-4)-2=0

We get rid of parentheses

6x-6x+4-2=0

We add all the numbers together, and all the variables

2!=0

There is no solution for this equation

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