6(1+2v)=5(3v-1)+8v

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Solution for 6(1+2v)=5(3v-1)+8v equation: 



6(1+2v)=5(3v-1)+8v

We move all terms to the left:

6(1+2v)-(5(3v-1)+8v)=0

We add all the numbers together, and all the variables

6(2v+1)-(5(3v-1)+8v)=0

We multiply parentheses

12v-(5(3v-1)+8v)+6=0



We calculate terms in parentheses: -(5(3v-1)+8v), so:

5(3v-1)+8v

We add all the numbers together, and all the variables

8v+5(3v-1)

We multiply parentheses

8v+15v-5

We add all the numbers together, and all the variables

23v-5

Back to the equation:

-(23v-5)



We get rid of parentheses

12v-23v+5+6=0

We add all the numbers together, and all the variables

-11v+11=0

We move all terms containing v to the left, all other terms to the right

-11v=-11

v=-11/-11

v=1

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