2y-8+y=-3(y-1)+1

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Solution for 2y-8+y=-3(y-1)+1 equation: 



2y-8+y=-3(y-1)+1

We move all terms to the left:

2y-8+y-(-3(y-1)+1)=0

We add all the numbers together, and all the variables

3y-(-3(y-1)+1)-8=0



We calculate terms in parentheses: -(-3(y-1)+1), so:

-3(y-1)+1

We multiply parentheses

-3y+3+1

We add all the numbers together, and all the variables

-3y+4

Back to the equation:

-(-3y+4)



We get rid of parentheses

3y+3y-4-8=0

We add all the numbers together, and all the variables

6y-12=0

We move all terms containing y to the left, all other terms to the right

6y=12

y=12/6

y=2

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