6(u-3)=9u+9

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Solution for 6(u-3)=9u+9 equation: 



6(u-3)=9u+9

We move all terms to the left:

6(u-3)-(9u+9)=0

We multiply parentheses

6u-(9u+9)-18=0

We get rid of parentheses

6u-9u-9-18=0

We add all the numbers together, and all the variables

-3u-27=0

We move all terms containing u to the left, all other terms to the right

-3u=27

u=27/-3

u=-9

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