-5(t+3)=1+2(t-3)

Solution for -5(t+3)=1+2(t-3) equation:

-5(t+3)=1+2(t-3)

We move all terms to the left:

-5(t+3)-(1+2(t-3))=0

We multiply parentheses

-5t-(1+2(t-3))-15=0


We calculate terms in parentheses: -(1+2(t-3)), so:

1+2(t-3)

determiningTheFunctionDomain
2(t-3)+1

We multiply parentheses

2t-6+1

We add all the numbers together, and all the variables

2t-5

Back to the equation:

-(2t-5)


We get rid of parentheses

-5t-2t+5-15=0

We add all the numbers together, and all the variables

-7t-10=0

We move all terms containing t to the left, all other terms to the right

-7t=10

t=10/-7

t=-1+3/7