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(q/q-4)+3=(4/3q-2)
We move all terms to the left:
(q/q-4)+3-((4/3q-2))=0
Domain of the equation: q-4)!=0
q∈R
Domain of the equation: 3q-2))!=0We get rid of parentheses
q∈R
q/q-((4/3q-2))-4+3=0
Fractions to decimals
-((4/3q-2))-4+3+1=0
We multiply all the terms by the denominator
-((4-4*3q-2))+3*3q-2))+1*3q-2))=0
We calculate terms in parentheses: -((4-4*3q-2)), so:Wy multiply elements
(4-4*3q-2)
We add all the numbers together, and all the variables
(-4*3q+2)
We get rid of parentheses
-4*3q+2
Wy multiply elements
-12q+2
Back to the equation:
-(-12q+2)
-(-12q+2)+9q-2))+1*3q-2))=0
We get rid of parentheses
12q+9q-2))+1*3q-2))-2=0
We add all the numbers together, and all the variables
21q-2))+1*3q-2))-2=0
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