6(u-2+1)=2(3u-5)

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Solution for 6(u-2+1)=2(3u-5) equation: 



6(u-2+1)=2(3u-5)

We move all terms to the left:

6(u-2+1)-(2(3u-5))=0

We add all the numbers together, and all the variables

6(u-1)-(2(3u-5))=0

We multiply parentheses

6u-(2(3u-5))-6=0



We calculate terms in parentheses: -(2(3u-5)), so:

2(3u-5)

We multiply parentheses

6u-10

Back to the equation:

-(6u-10)



We get rid of parentheses

6u-6u+10-6=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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