2y-8+2(6y+4)=-4(y+3)

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Solution for 2y-8+2(6y+4)=-4(y+3) equation:



2y-8+2(6y+4)=-4(y+3)
We move all terms to the left:
2y-8+2(6y+4)-(-4(y+3))=0
We multiply parentheses
2y+12y-(-4(y+3))+8-8=0
We calculate terms in parentheses: -(-4(y+3)), so:
-4(y+3)
We multiply parentheses
-4y-12
Back to the equation:
-(-4y-12)
We add all the numbers together, and all the variables
14y-(-4y-12)=0
We get rid of parentheses
14y+4y+12=0
We add all the numbers together, and all the variables
18y+12=0
We move all terms containing y to the left, all other terms to the right
18y=-12
y=-12/18
y=-2/3

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