3(v-5)=7v-35

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Solution for 3(v-5)=7v-35 equation: 



3(v-5)=7v-35

We move all terms to the left:

3(v-5)-(7v-35)=0

We multiply parentheses

3v-(7v-35)-15=0

We get rid of parentheses

3v-7v+35-15=0

We add all the numbers together, and all the variables

-4v+20=0

We move all terms containing v to the left, all other terms to the right

-4v=-20

v=-20/-4

v=+5

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