6(u+2)-3u=6

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Solution for 6(u+2)-3u=6 equation: 



6(u+2)-3u=6

We move all terms to the left:

6(u+2)-3u-(6)=0

We add all the numbers together, and all the variables

-3u+6(u+2)-6=0

We multiply parentheses

-3u+6u+12-6=0

We add all the numbers together, and all the variables

3u+6=0

We move all terms containing u to the left, all other terms to the right

3u=-6

u=-6/3

u=-2

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