6(n+7)=12-3(n-4)

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Solution for 6(n+7)=12-3(n-4) equation: 



6(n+7)=12-3(n-4)

We move all terms to the left:

6(n+7)-(12-3(n-4))=0

We multiply parentheses

6n-(12-3(n-4))+42=0



We calculate terms in parentheses: -(12-3(n-4)), so:

12-3(n-4)

determiningTheFunctionDomain
-3(n-4)+12

We multiply parentheses

-3n+12+12

We add all the numbers together, and all the variables

-3n+24

Back to the equation:

-(-3n+24)



We get rid of parentheses

6n+3n-24+42=0

We add all the numbers together, and all the variables

9n+18=0

We move all terms containing n to the left, all other terms to the right

9n=-18

n=-18/9

n=-2

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