6x+10=3(x-2)+4(x-1)

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Solution for 6x+10=3(x-2)+4(x-1) equation: 



6x+10=3(x-2)+4(x-1)

We move all terms to the left:

6x+10-(3(x-2)+4(x-1))=0



We calculate terms in parentheses: -(3(x-2)+4(x-1)), so:

3(x-2)+4(x-1)

We multiply parentheses

3x+4x-6-4

We add all the numbers together, and all the variables

7x-10

Back to the equation:

-(7x-10)



We get rid of parentheses

6x-7x+10+10=0

We add all the numbers together, and all the variables

-1x+20=0

We move all terms containing x to the left, all other terms to the right

-x=-20

x=-20/-1

x=+20

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