2(x+3)-5=1/4(8x+4)

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Solution for 2(x+3)-5=1/4(8x+4) equation: 



2(x+3)-5=1/4(8x+4)

We move all terms to the left:

2(x+3)-5-(1/4(8x+4))=0



Domain of the equation: 4(8x+4))!=0

x∈R



We multiply parentheses

2x-(1/4(8x+4))+6-5=0

We multiply all the terms by the denominator


2x*4(8x+4))-(1+6*4(8x+4))-5*4(8x+4))=0

We add all the numbers together, and all the variables

2x*4(8x+4))-(1+6*4(8x+4))-5*4(8x=0

Wy multiply elements

8x^2(8+96x^2(8=0

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