6(f+5)=2(f-6)

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Solution for 6(f+5)=2(f-6) equation: 



6(f+5)=2(f-6)

We move all terms to the left:

6(f+5)-(2(f-6))=0

We multiply parentheses

6f-(2(f-6))+30=0



We calculate terms in parentheses: -(2(f-6)), so:

2(f-6)

We multiply parentheses

2f-12

Back to the equation:

-(2f-12)



We get rid of parentheses

6f-2f+12+30=0

We add all the numbers together, and all the variables

4f+42=0

We move all terms containing f to the left, all other terms to the right

4f=-42

f=-42/4

f=-10+1/2

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