0,003t2+0,007t-34=0

Solution for 0,003t2+0,007t-34=0 equation:

0.003t^2+0.007t-34=0

a = 0.003; b = 0.007; c = -34;
Δ = b2-4ac
Δ = 0.0072-4·0.003·(-34)
Δ = 0.408049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.007)-\sqrt{0.408049}}{2*0.003}=\frac{-0.007-\sqrt{0.408049}}{0.006}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.007)+\sqrt{0.408049}}{2*0.003}=\frac{-0.007+\sqrt{0.408049}}{0.006}
$