6(b-7)=-2(5b-3)

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Solution for 6(b-7)=-2(5b-3) equation: 



6(b-7)=-2(5b-3)

We move all terms to the left:

6(b-7)-(-2(5b-3))=0

We multiply parentheses

6b-(-2(5b-3))-42=0



We calculate terms in parentheses: -(-2(5b-3)), so:

-2(5b-3)

We multiply parentheses

-10b+6

Back to the equation:

-(-10b+6)



We get rid of parentheses

6b+10b-6-42=0

We add all the numbers together, and all the variables

16b-48=0

We move all terms containing b to the left, all other terms to the right

16b=48

b=48/16

b=3

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