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2(x-6)(5x-4)=0
We multiply parentheses ..
2(+5x^2-4x-30x+24)=0
We multiply parentheses
10x^2-8x-60x+48=0
We add all the numbers together, and all the variables
10x^2-68x+48=0
a = 10; b = -68; c = +48;
Δ = b2-4ac
Δ = -682-4·10·48
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2704}=52$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-52}{2*10}=\frac{16}{20} =4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+52}{2*10}=\frac{120}{20} =6 $
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