4(1-4n)=5(n+5)

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Solution for 4(1-4n)=5(n+5) equation: 



4(1-4n)=5(n+5)

We move all terms to the left:

4(1-4n)-(5(n+5))=0

We add all the numbers together, and all the variables

4(-4n+1)-(5(n+5))=0

We multiply parentheses

-16n-(5(n+5))+4=0



We calculate terms in parentheses: -(5(n+5)), so:

5(n+5)

We multiply parentheses

5n+25

Back to the equation:

-(5n+25)



We get rid of parentheses

-16n-5n-25+4=0

We add all the numbers together, and all the variables

-21n-21=0

We move all terms containing n to the left, all other terms to the right

-21n=21

n=21/-21

n=-1

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