7(x+2)+(x+5)=12(x+1)+2

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Solution for 7(x+2)+(x+5)=12(x+1)+2 equation: 



7(x+2)+(x+5)=12(x+1)+2

We move all terms to the left:

7(x+2)+(x+5)-(12(x+1)+2)=0

We multiply parentheses

7x+(x+5)-(12(x+1)+2)+14=0

We get rid of parentheses

7x+x-(12(x+1)+2)+5+14=0



We calculate terms in parentheses: -(12(x+1)+2), so:

12(x+1)+2

We multiply parentheses

12x+12+2

We add all the numbers together, and all the variables

12x+14

Back to the equation:

-(12x+14)



We add all the numbers together, and all the variables

8x-(12x+14)+19=0

We get rid of parentheses

8x-12x-14+19=0

We add all the numbers together, and all the variables

-4x+5=0

We move all terms containing x to the left, all other terms to the right

-4x=-5

x=-5/-4

x=1+1/4

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