3+4(h+2)=2h+3(h+4)

Solution for 3+4(h+2)=2h+3(h+4) equation:

3+4(h+2)=2h+3(h+4)

We move all terms to the left:

3+4(h+2)-(2h+3(h+4))=0

We multiply parentheses

4h-(2h+3(h+4))+8+3=0


We calculate terms in parentheses: -(2h+3(h+4)), so:

2h+3(h+4)

We multiply parentheses

2h+3h+12

We add all the numbers together, and all the variables

5h+12

Back to the equation:

-(5h+12)


We add all the numbers together, and all the variables

4h-(5h+12)+11=0

We get rid of parentheses

4h-5h-12+11=0

We add all the numbers together, and all the variables

-1h-1=0

We move all terms containing h to the left, all other terms to the right

-h=1

h=1/-1

h=-1