6(b+2)+3(b+1)=5

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Solution for 6(b+2)+3(b+1)=5 equation: 



6(b+2)+3(b+1)=5

We move all terms to the left:

6(b+2)+3(b+1)-(5)=0

We multiply parentheses

6b+3b+12+3-5=0

We add all the numbers together, and all the variables

9b+10=0

We move all terms containing b to the left, all other terms to the right

9b=-10

b=-10/9

b=-1+1/9

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