6(8x-20)=4(10x-4)

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Solution for 6(8x-20)=4(10x-4) equation: 



6(8x-20)=4(10x-4)

We move all terms to the left:

6(8x-20)-(4(10x-4))=0

We multiply parentheses

48x-(4(10x-4))-120=0



We calculate terms in parentheses: -(4(10x-4)), so:

4(10x-4)

We multiply parentheses

40x-16

Back to the equation:

-(40x-16)



We get rid of parentheses

48x-40x+16-120=0

We add all the numbers together, and all the variables

8x-104=0

We move all terms containing x to the left, all other terms to the right

8x=104

x=104/8

x=13

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