(k/3)-(2k)+(4)=10

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Solution for (k/3)-(2k)+(4)=10 equation: 



(k/3)-(2k)+(4)=10

We move all terms to the left:

(k/3)-(2k)+(4)-(10)=0

We add all the numbers together, and all the variables

(+k/3)-2k+4-10=0

We add all the numbers together, and all the variables

-2k+(+k/3)-6=0

We get rid of parentheses

-2k+k/3-6=0

We multiply all the terms by the denominator


-2k*3+k-6*3=0

We add all the numbers together, and all the variables

k-2k*3-18=0

Wy multiply elements

k-6k-18=0

We add all the numbers together, and all the variables

-5k-18=0

We move all terms containing k to the left, all other terms to the right

-5k=18

k=18/-5

k=-3+3/5

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