5/2(x-6)=1/3(x+3)

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Solution for 5/2(x-6)=1/3(x+3) equation: 



5/2(x-6)=1/3(x+3)

We move all terms to the left:

5/2(x-6)-(1/3(x+3))=0



Domain of the equation: 2(x-6)!=0

x∈R





Domain of the equation: 3(x+3))!=0

x∈R



We calculate fractions


(15xx/(2(x-6)*3(x+3)))+(-2xx/(2(x-6)*3(x+3)))=0



We calculate terms in parentheses: +(15xx/(2(x-6)*3(x+3))), so:

15xx/(2(x-6)*3(x+3))

We multiply all the terms by the denominator


15xx

Back to the equation:

+(15xx)





We calculate terms in parentheses: +(-2xx/(2(x-6)*3(x+3))), so:

-2xx/(2(x-6)*3(x+3))

We multiply all the terms by the denominator


-2xx

Back to the equation:

+(-2xx)



We get rid of parentheses

15xx-2xx=0

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