6(6y-4)+1=5(5y-1)+14

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Solution for 6(6y-4)+1=5(5y-1)+14 equation:



6(6y-4)+1=5(5y-1)+14
We move all terms to the left:
6(6y-4)+1-(5(5y-1)+14)=0
We multiply parentheses
36y-(5(5y-1)+14)-24+1=0
We calculate terms in parentheses: -(5(5y-1)+14), so:
5(5y-1)+14
We multiply parentheses
25y-5+14
We add all the numbers together, and all the variables
25y+9
Back to the equation:
-(25y+9)
We add all the numbers together, and all the variables
36y-(25y+9)-23=0
We get rid of parentheses
36y-25y-9-23=0
We add all the numbers together, and all the variables
11y-32=0
We move all terms containing y to the left, all other terms to the right
11y=32
y=32/11
y=2+10/11

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