35=3+2(b+7)

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Solution for 35=3+2(b+7) equation: 



35=3+2(b+7)

We move all terms to the left:

35-(3+2(b+7))=0



We calculate terms in parentheses: -(3+2(b+7)), so:

3+2(b+7)

determiningTheFunctionDomain
2(b+7)+3

We multiply parentheses

2b+14+3

We add all the numbers together, and all the variables

2b+17

Back to the equation:

-(2b+17)



We get rid of parentheses

-2b-17+35=0

We add all the numbers together, and all the variables

-2b+18=0

We move all terms containing b to the left, all other terms to the right

-2b=-18

b=-18/-2

b=+9

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