3(4a-10)+12=6(3+3a)

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Solution for 3(4a-10)+12=6(3+3a) equation: 



3(4a-10)+12=6(3+3a)

We move all terms to the left:

3(4a-10)+12-(6(3+3a))=0

We add all the numbers together, and all the variables

3(4a-10)-(6(3a+3))+12=0

We multiply parentheses

12a-(6(3a+3))-30+12=0



We calculate terms in parentheses: -(6(3a+3)), so:

6(3a+3)

We multiply parentheses

18a+18

Back to the equation:

-(18a+18)



We add all the numbers together, and all the variables

12a-(18a+18)-18=0

We get rid of parentheses

12a-18a-18-18=0

We add all the numbers together, and all the variables

-6a-36=0

We move all terms containing a to the left, all other terms to the right

-6a=36

a=36/-6

a=-6

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