(2x+5)(x-2)=(x-1)(2x-1)

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Solution for (2x+5)(x-2)=(x-1)(2x-1) equation: 



(2x+5)(x-2)=(x-1)(2x-1)

We move all terms to the left:

(2x+5)(x-2)-((x-1)(2x-1))=0

We multiply parentheses ..

(+2x^2-4x+5x-10)-((x-1)(2x-1))=0



We calculate terms in parentheses: -((x-1)(2x-1)), so:

(x-1)(2x-1)

We multiply parentheses ..

(+2x^2-1x-2x+1)

We get rid of parentheses

2x^2-1x-2x+1

We add all the numbers together, and all the variables

2x^2-3x+1

Back to the equation:

-(2x^2-3x+1)



We get rid of parentheses

2x^2-2x^2-4x+5x+3x-10-1=0

We add all the numbers together, and all the variables

4x-11=0

We move all terms containing x to the left, all other terms to the right

4x=11

x=11/4

x=2+3/4

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