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6(6v/6)-5=1/6v
We move all terms to the left:
6(6v/6)-5-(1/6v)=0
Domain of the equation: 6v)!=0We add all the numbers together, and all the variables
v!=0/1
v!=0
v∈R
6(+6v/6)-(+1/6v)-5=0
We multiply parentheses
36v-(+1/6v)-5=0
We get rid of parentheses
36v-1/6v-5=0
We multiply all the terms by the denominator
36v*6v-5*6v-1=0
Wy multiply elements
216v^2-30v-1=0
a = 216; b = -30; c = -1;
Δ = b2-4ac
Δ = -302-4·216·(-1)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-42}{2*216}=\frac{-12}{432} =-1/36 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+42}{2*216}=\frac{72}{432} =1/6 $
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