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(6x+12)=(2x+60)
We move all terms to the left:
(6x+12)-((2x+60))=0
We get rid of parentheses
6x-((2x+60))+12=0
We calculate terms in parentheses: -((2x+60)), so:We get rid of parentheses
(2x+60)
We get rid of parentheses
2x+60
Back to the equation:
-(2x+60)
6x-2x-60+12=0
We add all the numbers together, and all the variables
4x-48=0
We move all terms containing x to the left, all other terms to the right
4x=48
x=48/4
x=12
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