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1/2x+32=6x+4.5
We move all terms to the left:
1/2x+32-(6x+4.5)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
1/2x-6x-4.5+32=0
We multiply all the terms by the denominator
-6x*2x-(4.5)*2x+32*2x+1=0
We multiply parentheses
-6x*2x-9x+32*2x+1=0
Wy multiply elements
-12x^2-9x+64x+1=0
We add all the numbers together, and all the variables
-12x^2+55x+1=0
a = -12; b = 55; c = +1;
Δ = b2-4ac
Δ = 552-4·(-12)·1
Δ = 3073
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-\sqrt{3073}}{2*-12}=\frac{-55-\sqrt{3073}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+\sqrt{3073}}{2*-12}=\frac{-55+\sqrt{3073}}{-24} $
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