6(5r-3)=1/3(24r+12)

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Solution for 6(5r-3)=1/3(24r+12) equation: 



6(5r-3)=1/3(24r+12)

We move all terms to the left:

6(5r-3)-(1/3(24r+12))=0



Domain of the equation: 3(24r+12))!=0

r∈R



We multiply parentheses

30r-(1/3(24r+12))-18=0

We multiply all the terms by the denominator


30r*3(24r+12))-(1-18*3(24r+12))=0

Wy multiply elements

90r^2(2-54r(2=0

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