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4(3w+5)=2-3(w-6)
We move all terms to the left:
4(3w+5)-(2-3(w-6))=0
We multiply parentheses
12w-(2-3(w-6))+20=0
We calculate terms in parentheses: -(2-3(w-6)), so:We get rid of parentheses
2-3(w-6)
determiningTheFunctionDomain -3(w-6)+2
We multiply parentheses
-3w+18+2
We add all the numbers together, and all the variables
-3w+20
Back to the equation:
-(-3w+20)
12w+3w-20+20=0
We add all the numbers together, and all the variables
15w=0
w=0/15
w=0
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