6(4y+8)=-3(2y-2)

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Solution for 6(4y+8)=-3(2y-2) equation: 



6(4y+8)=-3(2y-2)

We move all terms to the left:

6(4y+8)-(-3(2y-2))=0

We multiply parentheses

24y-(-3(2y-2))+48=0



We calculate terms in parentheses: -(-3(2y-2)), so:

-3(2y-2)

We multiply parentheses

-6y+6

Back to the equation:

-(-6y+6)



We get rid of parentheses

24y+6y-6+48=0

We add all the numbers together, and all the variables

30y+42=0

We move all terms containing y to the left, all other terms to the right

30y=-42

y=-42/30

y=-1+2/5

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