4x-12/4x=0

Solution for 4x-12/4x=0 equation:

4x-12/4x=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We multiply all the terms by the denominator


4x*4x-12=0

Wy multiply elements

16x^2-12=0

a = 16; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·16·(-12)
Δ = 768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{768}=\sqrt{256*3}=\sqrt{256}*\sqrt{3}=16\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{3}}{2*16}=\frac{0-16\sqrt{3}}{32}
=-\frac{16\sqrt{3}}{32}
=-\frac{\sqrt{3}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{3}}{2*16}=\frac{0+16\sqrt{3}}{32}
=\frac{16\sqrt{3}}{32}
=\frac{\sqrt{3}}{2}
$