6(3x-2)=9(2x-1)+

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Solution for 6(3x-2)=9(2x-1)+ equation: 



6(3x-2)=9(2x-1)+

We move all terms to the left:

6(3x-2)-(9(2x-1)+)=0

We multiply parentheses

18x-(9(2x-1)+)-12=0



We calculate terms in parentheses: -(9(2x-1)+), so:

9(2x-1)+

We add all the numbers together, and all the variables

9(2x-1)

We multiply parentheses

18x-9

Back to the equation:

-(18x-9)



We get rid of parentheses

18x-18x+9-12=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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