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4(2x-6)=3(2x-4)+-2x
We move all terms to the left:
4(2x-6)-(3(2x-4)+-2x)=0
We use the square of the difference formula
4(2x-6)-(3(2x-4)-2x)=0
We multiply parentheses
8x-(3(2x-4)-2x)-24=0
We calculate terms in parentheses: -(3(2x-4)-2x), so:We get rid of parentheses
3(2x-4)-2x
We add all the numbers together, and all the variables
-2x+3(2x-4)
We multiply parentheses
-2x+6x-12
We add all the numbers together, and all the variables
4x-12
Back to the equation:
-(4x-12)
8x-4x+12-24=0
We add all the numbers together, and all the variables
4x-12=0
We move all terms containing x to the left, all other terms to the right
4x=12
x=12/4
x=3
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