4(2x-6)=3(2x-4)+-2

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Solution for 4(2x-6)=3(2x-4)+-2 equation: 



4(2x-6)=3(2x-4)+-2

We move all terms to the left:

4(2x-6)-(3(2x-4)+-2)=0

We use the square of the difference formula

4(2x-6)-(3(2x-4)-2)=0

We multiply parentheses

8x-(3(2x-4)-2)-24=0



We calculate terms in parentheses: -(3(2x-4)-2), so:

3(2x-4)-2

We multiply parentheses

6x-12-2

We add all the numbers together, and all the variables

6x-14

Back to the equation:

-(6x-14)



We get rid of parentheses

8x-6x+14-24=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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