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6(3x+4)=16x+2(x+12)
We move all terms to the left:
6(3x+4)-(16x+2(x+12))=0
We multiply parentheses
18x-(16x+2(x+12))+24=0
We calculate terms in parentheses: -(16x+2(x+12)), so:We get rid of parentheses
16x+2(x+12)
We multiply parentheses
16x+2x+24
We add all the numbers together, and all the variables
18x+24
Back to the equation:
-(18x+24)
18x-18x-24+24=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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