1/4(8-3a)=1/2(3a+40)

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Solution for 1/4(8-3a)=1/2(3a+40) equation: 



1/4(8-3a)=1/2(3a+40)

We move all terms to the left:

1/4(8-3a)-(1/2(3a+40))=0



Domain of the equation: 4(8-3a)!=0

a∈R





Domain of the equation: 2(3a+40))!=0

a∈R



We add all the numbers together, and all the variables

1/4(-3a+8)-(1/2(3a+40))=0

We calculate fractions


(2a3/(4(-3a+8)*2(3a+40)))+(-4a0/(4(-3a+8)*2(3a+40)))=0



We calculate terms in parentheses: +(2a3/(4(-3a+8)*2(3a+40))), so:

2a3/(4(-3a+8)*2(3a+40))

We multiply all the terms by the denominator


2a3

We add all the numbers together, and all the variables

2a^3

We do not support eapression: a^3

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