2/5x+25=4/2x+30

Solution for 2/5x+25=4/2x+30 equation:

2/5x+25=4/2x+30

We move all terms to the left:

2/5x+25-(4/2x+30)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 2x+30)!=0

x∈R


We get rid of parentheses

2/5x-4/2x-30+25=0

We calculate fractions


4x/10x^2+(-20x)/10x^2-30+25=0

We add all the numbers together, and all the variables

4x/10x^2+(-20x)/10x^2-5=0

We multiply all the terms by the denominator


4x+(-20x)-5*10x^2=0

Wy multiply elements

-50x^2+4x+(-20x)=0

We get rid of parentheses

-50x^2+4x-20x=0

We add all the numbers together, and all the variables

-50x^2-16x=0

a = -50; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·(-50)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*-50}=\frac{0}{-100}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*-50}=\frac{32}{-100}
=-8/25
$