6(3n+2)=7(9n+3)+1

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Solution for 6(3n+2)=7(9n+3)+1 equation: 



6(3n+2)=7(9n+3)+1

We move all terms to the left:

6(3n+2)-(7(9n+3)+1)=0

We multiply parentheses

18n-(7(9n+3)+1)+12=0



We calculate terms in parentheses: -(7(9n+3)+1), so:

7(9n+3)+1

We multiply parentheses

63n+21+1

We add all the numbers together, and all the variables

63n+22

Back to the equation:

-(63n+22)



We get rid of parentheses

18n-63n-22+12=0

We add all the numbers together, and all the variables

-45n-10=0

We move all terms containing n to the left, all other terms to the right

-45n=10

n=10/-45

n=-2/9

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