4(k-7)=2(k+12)

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Solution for 4(k-7)=2(k+12) equation: 



4(k-7)=2(k+12)

We move all terms to the left:

4(k-7)-(2(k+12))=0

We multiply parentheses

4k-(2(k+12))-28=0



We calculate terms in parentheses: -(2(k+12)), so:

2(k+12)

We multiply parentheses

2k+24

Back to the equation:

-(2k+24)



We get rid of parentheses

4k-2k-24-28=0

We add all the numbers together, and all the variables

2k-52=0

We move all terms containing k to the left, all other terms to the right

2k=52

k=52/2

k=26

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