(6x-9)(9x+9)=0

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Solution for (6x-9)(9x+9)=0 equation:



(6x-9)(9x+9)=0
We multiply parentheses ..
(+54x^2+54x-81x-81)=0
We get rid of parentheses
54x^2+54x-81x-81=0
We add all the numbers together, and all the variables
54x^2-27x-81=0
a = 54; b = -27; c = -81;
Δ = b2-4ac
Δ = -272-4·54·(-81)
Δ = 18225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18225}=135$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-135}{2*54}=\frac{-108}{108} =-1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+135}{2*54}=\frac{162}{108} =1+1/2 $

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