6(3+d)+3d=9(2+d)

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Solution for 6(3+d)+3d=9(2+d) equation: 



6(3+d)+3d=9(2+d)

We move all terms to the left:

6(3+d)+3d-(9(2+d))=0

We add all the numbers together, and all the variables

6(d+3)+3d-(9(d+2))=0

We add all the numbers together, and all the variables

3d+6(d+3)-(9(d+2))=0

We multiply parentheses

3d+6d-(9(d+2))+18=0



We calculate terms in parentheses: -(9(d+2)), so:

9(d+2)

We multiply parentheses

9d+18

Back to the equation:

-(9d+18)



We add all the numbers together, and all the variables

9d-(9d+18)+18=0

We get rid of parentheses

9d-9d-18+18=0

We add all the numbers together, and all the variables

=0

d=0/1

d=0

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