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7c+2c-4(2c+1)=3(c-3)
We move all terms to the left:
7c+2c-4(2c+1)-(3(c-3))=0
We add all the numbers together, and all the variables
9c-4(2c+1)-(3(c-3))=0
We multiply parentheses
9c-8c-(3(c-3))-4=0
We calculate terms in parentheses: -(3(c-3)), so:We add all the numbers together, and all the variables
3(c-3)
We multiply parentheses
3c-9
Back to the equation:
-(3c-9)
c-(3c-9)-4=0
We get rid of parentheses
c-3c+9-4=0
We add all the numbers together, and all the variables
-2c+5=0
We move all terms containing c to the left, all other terms to the right
-2c=-5
c=-5/-2
c=2+1/2
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