8-x+2(x+1)=-(3x-2)-4

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Solution for 8-x+2(x+1)=-(3x-2)-4 equation: 



8-x+2(x+1)=-(3x-2)-4

We move all terms to the left:

8-x+2(x+1)-(-(3x-2)-4)=0

We add all the numbers together, and all the variables

-1x+2(x+1)-(-(3x-2)-4)+8=0

We multiply parentheses

-1x+2x-(-(3x-2)-4)+2+8=0



We calculate terms in parentheses: -(-(3x-2)-4), so:

-(3x-2)-4

We get rid of parentheses

-3x+2-4

We add all the numbers together, and all the variables

-3x-2

Back to the equation:

-(-3x-2)



We add all the numbers together, and all the variables

x-(-3x-2)+10=0

We get rid of parentheses

x+3x+2+10=0

We add all the numbers together, and all the variables

4x+12=0

We move all terms containing x to the left, all other terms to the right

4x=-12

x=-12/4

x=-3

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